Market Indexes: Major U.S. Equity Indexes closed higher
SPX Candle: Higher High, Higher Low, Higher Close - Trend Candle
FED Posture: Quantitative Tightening (QT)
Today's post is occurring in two parts. The first part shows the S&P500 Cash Index chart - close only - using five minute closes to simulate one of Neely's techniques for wave counting. Besides simulation, we think this view can provide unparalleled insight into the nature of this wave, and wave counting in general. Yes, using 5-minute closes might leave out a data point or two, but, yesterday, we used the hourly futures with every data point included, even overnight ones, and one can arrive at a slightly better count by using cash chart.
Further, we know we verified all of the degree labeling requirements on the hourly futures. So, we will not dispute those in this chart. The main purpose of this chart is to show the form of the wave, without a lot of the distractions from the bars.
S&P500 Cash Index - 5 Minute Line - Neely Style |
The first thing we notice about cash, is that where it was possible to call wave ((2)) a sharp in the futures, this is not possible in cash.
Why?
This is because of the Neely guideline that a line from zero to wave ((2)) must not cut off any part of a wave ((3)). Showing wave two at almost any earlier location would do that. And, at this location, wave ((2)) overlaps wave ((1)) as required for wave ((2)) to be "corrective" to wave ((1)).
Wave ((2)) thus becomes a "running wave" with a higher (B) wave, and that is important. It means that wave ((4)) should only be a 'short sharp' or a longer triangle. If the fourth wave were to become longer than two in time, then it would have to be a triangle. But, keep in mind this is an a wave up, overall. As such, it can throw a wrinkle or two into the impulse. It doesn't have to but it can. The wrinkle would be that that fourth wave is shorter in time than the second wave for it's alternation. This is the real discussion of alternates in wave analysis. In either case, the (B) wave of ((4)) should not cross over the top to alternate with ((2)). As the chart shows, it didn't.
The second part of this post consists of reminding us that the daily ES price is still over SMA-18, and therefore still has a positive bias. There is some potential for two things over the weekend: a) the results of the G-20 meeting. If negative, they could temporarily bring a down draft. If positive, perhaps a gap up. b) Monday will be the first day of the new month with the usual potential for inflows into the market, as we have written about many times before (company bonuses, dividend reinvestment plans, 401k's, etc.). If G-20 is positive and inflows occur, and a gap up results, then there is an alternate count here where ((1)) and ((2)) are actually ((A)) and ((B)) of the (y) wave upward to minute ((ii)).
That latter interpretation would be the ((A)) wave as a Leading Diagonal.
There is nothing that says that wave ((5)) in the above chart is done either. It could be but it doesn't have to be.
Take it easy. Rest up. Have a good start to your evening and to your weekend.
TraderJoe
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P.S. In trying out the ALTERNATE count of A, as a diagonal at the bottom, and B the very brief retrace, it creates a degree violation that 1 of C, at or near any of the peaks of the high, which would be a sub-wave of lower degree than A, yet it would be longer than A in price, which does not work. Good news.
1 of C (in the ALTERNATE) would have needed to be located near one of the highs because the potential gap up would be a iii of 3 of C.
Bottom line: best count at this time is a five wave move from the bottom, most likely as an A wave to Friday's high.
Thanks Joe
ReplyDeleteWeclome Fatima.
Deletethanks joe
ReplyDeleteif you have time please post the alternate. enjoy your weekend
Mark,
DeleteI think Joe is saying is that from the bottom on 11-20 that first little rise and almost complete retrace could be counted as a & b of y and the large rise that follows would be c of y which would complete minute (ii) as opposed to combining everything into 1 impulse to make a of y.
Essentially.
Deletethanks gentlemen
Deleteis there any reason or guidelines to determine if we are in a c wave or an a wave
DeleteMeasuring on my chart, ((1)) = 38.36 and (iii) of ((3)) = 41.02. That is a degree violation on the cash chart - correct?
ReplyDeleteNo. Those were verified on futures.
DeleteI see, ok.
DeleteGreat post Joe!
ReplyDeleteRegarding the alternate, would ((3)) on this chart be (1) of ((C))? Or would you prefer the same place for (3) of ((C)) but an extended fifht wave instead to get (y) over 2815?
Have a great weekend you to!
Yes. Erik. As far as I can tell in the alternate ((3)) would be ((1)) of c. There would be no alternation between b and ((2)) of c.
DeleteBut is it not less likely with ((2)) of c as a triangle? Is that why you have it as an alternate?
DeleteSee my comment below.
DeleteGreat Post Joe, thanks for the articulation. Simply brilliant.
ReplyDeleteWelcome!
DeleteAwesome post as usual Joe! I remain long and strong!
ReplyDeleteSee comment below.
DeleteIn trying out the ALTERNATE count of A, as a diagonal at the bottom, and B the very brief retrace, it creates a degree violation that 1 of C, at or near any of the peaks of the high, which would be a sub-wave of lower degree than A, yet it would be longer than A in price, which does not work. Good news.
ReplyDelete1 of C (in the ALTERNATE)would have needed to be located near one of the highs because the potential gap up would be a iii of 3 of C.
Bottom line: best count at this time is a five wave move from the bottom, most likely as an A wave to Friday's high.
This comment added as a formal post-script to the commentary above.
DeleteSee my comment below.
ReplyDeleteLOVE your work! In the proposed wave 2 up, as this should not be a flat as the B wave did not retrace 90% of A, and wave 2 is never (?) a triangle, then we must have a zig zag, yes? If so, then wave C must be an impulse. Though you discounted your alternate count because of degree violation, IF let's say there was no violation, how could Y of W X Y be an a,b,c, which is a zig zag, not an impulse as zig zags are 5/3/5 formations? Thanks in advance for your surely most helpful answer!
ReplyDeleteThanks for the superb comment. I have tried to answer your questions in full with a new post on Saturday. Let me know if anything should remain unclear.
DeleteHi Joe, i am unclear about a few things concerning wave violations. I am having hard time when it comes to wave 4 -
ReplyDeletehistorically there are counts which have been ruled out based on size of a wave 4 (relative to higher degree wave 4) and
along different thought yesterday you said wave 4 was not restricted by subwave 4 of wave 3.
So here's my running list and there are a few gaps if you can help:
100% certain:
1) wave 3 up subwaves less than wave 1.
2) wave 5 up wubwaves less than the larger of wave 1 and wave 3.
3) wave 3 subwave 2 less than wave 2.
80% certain
4) wave 5 subwave 2 must be less than wave 2
uncertain
5) subwave 4 in wave 5 must be less than wave 4
6) wave 4 relationship to subwave 4 in both wave 1 and 3.
7) for purpose of clarity, assuming we have an ipo with no price history so no higher degree waves.
a) wave 1 and 2 will have no degree restrictions just need to satisfy EW rules and internally follow wave degree rules, but dont restrict each other.
b) all up subwaves of waves 3 and 5 will be restricted thus restricting size of wave 3 and 5.
c) subwave 2 of both 3 and 5 will have identical restriction
d) no restriction on wave 1 subwave 4 and wave 3 subwave 4 other than EW rules.
e) no restriction on wave 4 based on subwaves 4 of wave 1 and 3
e) no restriction on wave 5 subwave 4 basd on wave 4
thanks again. I need to understand rules if i'm going to measure and not go by looks and feel.
this may clear up a lot: as your are measuring from 0, you can find your count invalidated, when you get into wave 3: subwaves 1 2 3 5 have restrictions. then wave 4 has no restrictions (there isnt a higher degree wave 4 in the measurement from 0). then wave 5 subwaves 1 2 3 5 are restricted. And wave 5 subwave 4 is restricted by wave 4. The only time there is wave 4 restriction is when its a subwave of wave 5.
DeleteNo, not quite. There is 'always' a higher degree wave four 'somewhere' on the chart!
Deletesuppose 12345 abc zigzag... 4th wave of a and c restricted by wave 4 of 12345?
ReplyDeleteMost definitely, but that is not all that 4 of a & c are restricted by.
Deletejoe, is wave 4 of 5 restricted by a preceding smaller degree wave 4 of 3. Once a wave is labeled with no violations can any future action make it a violation. do comparisons run both ways through time?
ReplyDeleteMarc .. your symbols are half of your confusion. You once posted the symbology of a 1212 count. There is 'no' such thing. You 'must' take the time to learn and think in terms of 1, 2, ((i)), ((ii)) or ((iv)) of 5 vs. ((iv)) of 3 in the above note. If you will do that, you will answer half of your questions. You did it (in one incorrect way) in the fourth wave question with at least showing a lower case a,b,c so I knew they were different than 4. You must continue to do so - but be even more formal about it - in the future.
Delete